What will console.log(number++) and console.log(++number) output for the variable defined as let number = 0?

What will console.log(number++) and console.log(++number) output for the variable defined as let number = 0?

• A. 1 1 2
• B. 1 2 2
• C. 0 2 2
• D. 0 1 2

Answer: (C)

The output for the expressions `console.log(number++)` and `console.log(++number)` when the variable `number` is defined as `let number = 0` will be `0` for the first log and `2` for the second. Initially, `number` is set to `0`. When the expression `console.log(number++)` is executed, the current value of `number` (which is `0`) is logged to the console. The post-increment operator (`number++`) increases the value of `number` by `1` after the current value has been returned. Therefore, `0` is printed to the console, and afterward, `number` becomes `1`. Next, when `console.log(++number)` is executed, the pre-increment operator (`++number`) increases the value of `number` by `1` before it's logged. Since `number` was `1` after the previous operation, it becomes `2` with this pre-increment operation, and then `2` is printed to the console. Thus, the final sequence of outputs is `0` (from the post-increment) followed by `2` (from the pre-increment), which fits the output from the

The output for the expressions console.log(number++) and console.log(++number) when the variable number is defined as let number = 0 will be 0 for the first log and 2 for the second.

Initially, number is set to 0. When the expression console.log(number++) is executed, the current value of number (which is 0) is logged to the console. The post-increment operator (number++) increases the value of number by 1 after the current value has been returned. Therefore, 0 is printed to the console, and afterward, number becomes 1.

Next, when console.log(++number) is executed, the pre-increment operator (++number) increases the value of number by 1 before it's logged. Since number was 1 after the previous operation, it becomes 2 with this pre-increment operation, and then 2 is printed to the console.

Thus, the final sequence of outputs is 0 (from the post-increment) followed by 2 (from the pre-increment), which fits the output from the