What will console.log(number++) and console.log(++number) output for the variable defined as let number = 0?

The output for the expressions console.log(number++) and console.log(++number) when the variable number is defined as let number = 0 will be 0 for the first log and 2 for the second.

Initially, number is set to 0. When the expression console.log(number++) is executed, the current value of number (which is 0) is logged to the console. The post-increment operator (number++) increases the value of number by 1 after the current value has been returned. Therefore, 0 is printed to the console, and afterward, number becomes 1.

Next, when console.log(++number) is executed, the pre-increment operator (++number) increases the value of number by 1 before it's logged. Since number was 1 after the previous operation, it becomes 2 with this pre-increment operation, and then 2 is printed to the console.

Thus, the final sequence of outputs is 0 (from the post-increment) followed by 2 (from the pre-increment), which fits the output from the